Sum of alternative Numbers

Given a values N. Find the sum's of alternative the numbers from 0 to N.

Input Format

Single value represents N

Constraints

0<= N <= 10,00,000

Output Format

Two spaceseperated value represents sum's of alternative values from 0 to N.

Sample Input 0

5

Sample Output 0

6 9

Explanation 0

Given N value 5.

The numbers from 0 to 5 is 0,1,2,3,4,5

Alternative Sum1=0+2+4=6

alternative sum2= 1+3+5=9

Sample Input 1

1

Sample Output 1

0 1

Source Code:

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {
long long int n,c=0,c1=0,j=1,i=0;
    scanf("%lld",&n);
   while(i<=n)
        {
            c=c+i;
            i=i+2;
        }
        while(j<=n)
        {
            c1=c1+j;
            j=j+2;
        }
    printf("%lld %lld",c,c1);
    return 0;
}